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What is relative speed, and when do you add or subtract?
Relative speed is the speed one object seems to have when you watch it from the other: how fast the gap between them changes. Two cars heading north at 80 and 60 km/h: each hour the faster gains 80 โ 60 = 20 km. Turn one round to face the other and the gap shrinks by 80 + 60 = 140 km an hour. That's the whole rule.
- โขS1 โ S2
- โขS1 + S2
| Test | Same direction | Opposite directions |
|---|---|---|
| 72 and 54 km/h | 18 km/h | 126 km/h |
| Gap changes each hour by | the difference | the sum |
Bigger relative speed, shorter crossing: 70 s vs 10 s.
How do you solve train crossing questions?
A train is not a dot. It has crossed a pole only when its last coach passes it, so the front has travelled the train's full length. It has crossed a platform when the last coach leaves the far end: train plus platform. Get the distance right and the rest is one division.
| The train crossesโฆ | Distance to cover | Speed to use |
|---|---|---|
| A pole, signal or standing person | Train's length | Train's speed |
| A platform, bridge or tunnel | Train + platform | Train's speed |
| A person walking or cycling | Train's length | Difference (same way) or sum (towards) |
| Another train | Both lengths added | Difference (same way) or sum (opposite) |
- 1Pole: the train covers its own 210 m. Speed = 210 รท 14 = 15 m/s.
- 2Platform: distance = 210 + 330 = 540 m.
- 3Time = 540 รท 15 = 36 s.
- 1Rohan has no real length, so the distance is the train's 280 m.
- 2Relative speed = 280 รท 16 = 17.5 m/s = 63 km/h.
- 3Same direction: relative = train โ Rohan, so train = 63 + 18 = 81 km/h.
- 1The extra 8 s covered the 200 m platform: speed = 25 m/s.
- 2Length = 25 ร 10 = 250 m.
- 3Other train: 54 km/h = 15 m/s. Opposite, so relative = 25 + 15 = 40 m/s.
- 4Time = (250 + 150) รท 40 = 10 s.
How do meeting and catch-up problems work?
Same rule, minus the lengths. Heading towards each other, the gap closes at the sum of speeds; in a chase, at the difference. Time = gap รท relative speed. The only extra job is finding the gap at the moment both are moving.
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9:00Aarav leaves at 40 km/h
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9:30Zoya leaves at 60 km/hAarav already has 40 ร ยฝ = 20 km head start.
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GapClosing speed = 60 โ 40 = 20 km/h20 km รท 20 km/h = 1 hour.
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10:30Caught, 60 km from homeCheck: 60 ร 1 = 40 ร 1.5 = 60 km. โ
Now flip it. Two buses leave towns 180 km apart together, driving towards each other at 50 and 40 km/h. The gap shrinks at 90 km/h, so they meet after 2 hours, 100 km from the first town: distances split in the ratio of speeds, 50 : 40.
How do race questions like "A beats B by 20 m" work?
Runners start together and run for the same time, so distances covered are in the ratio of their speeds. "A beats B by 20 m in a 100 m race" means that when A touches 100 m, B is at 80 m. B's speed is 80/100 of A's, all race long.
| The race saysโฆ | What it means | In a 100 m race |
|---|---|---|
| A beats B by 20 m | B is 20 m short at A's finish | B runs 80 while A runs 100 |
| A beats B by 5 s | B finishes 5 s after A | B's time = A's time + 5 |
| A beats B by 20 m or 5 s | B needs 5 s for the last 20 m | B's speed = 4 m/s |
| A gives B a 10 m start | B begins 10 m ahead | B runs only 90 m |
- 1When Zoya finishes, Aarav is at 950 m.
- 2Meher runs 900 m per 1,000 of Aarav's, so 0.9 of whatever Aarav runs.
- 3At Aarav's 950, Meher is at 950 ร 0.9 = 855 m. Gap = 145 m.
How do trains hide inside a CLAT caselet?
Since 2020, trains arrive as a paragraph, not a one-liner. Pull the numbers into a table first. Say Rampur Junction's 300 m platform sees Train P (300 m, 90 km/h), Train Q (200 m, 72 km/h) and Train R (450 m, 54 km/h); P and Q run east, R west.
P is longer than Q yet quicker. Compute; don't eyeball.
Then the questions pair trains. P overtaking Q: (300 + 200) รท (25 โ 20) = 100 s. P crossing R head-on: (300 + 450) รท (25 + 15) = 18.75 s.
Which traps cost the most marks?
Boats and streams: the same idea with water
Boat speed b, river speed s. Downstream: b + s. Upstream: b โ s. So s is half the difference of the two.
How CLAT asked it
A train 600 meters long is running at a speed of 90 kms/hr. If it crosses a tunnel in one minute, then the length of the tunnel is:
Reveal answer + reasoning
- A โ No correct route gives 500; a guess near the train's length.
- B โ Also no route. Convert, multiply, subtract the train: 900.
- C โ Assumes the tunnel equals the train. The 1,500 m total leaves 900 for the tunnel.
In a 100 meters race, A beats B by 20 meters B beats C by 5 meters. In the same race, A beats C by:
Reveal answer + reasoning
Faster: 0.8 ร 0.95 = 0.76. About 25 seconds.
- A โ No ratio route gives 26.
- B โ Adds 20 + 5. B's 5 m lead is over 100 m; when A finishes, B has run only 80, so C trails B by 4.
- D โ No ratio route gives 22.
๐
Myth
The relative speed of two trains is the sum of their speeds.
Tap to bust it โ
๐
Myth
Crossing a 300 m platform means covering 300 m.
Tap to bust it โ
๐
Myth
If A beats B by 20 m and B beats C by 5 m, A beats C by 25 m.
Tap to bust it โ
๐
Myth
A train passes a walker in the same time whichever way he walks.
Tap to bust it โ
Can you do these five?
Q1. How long does it take?
54 km/h = 15 m/s; (360 + 240) รท 15 = 40 s. 24 s ignores the bridge.Q2. How long do they take to cross each other?
Relative speed 90 km/h = 25 m/s; 300 รท 25 = 12 s. 108 s is the same-direction answer.Q3. How long after setting off does Kabir catch him?
Head start 10 km; closing speed 15 km/h; 10 รท 15 h = 40 min.Q4. What is Meher's time for the race?
Rohan runs 25 m in 5 s: 5 m/s, so 40 s for 200 m. Meher is 5 s quicker: 35 s.Q5. What is the speed of the stream?
Down 12, up 8 km/h. Stream = (12 โ 8) รท 2 = 2 km/h. 10 is the boat.- Relative speed = how fast the gap changes: difference for the same direction, sum for opposite.
- A crossing train covers its length + the other object's.
- Catch-up = head start รท difference; meeting = gap รท sum.
- In races, multiply leads as ratios; never add them.
- No direction or a missing length in a caselet = cannot be determined.
- Relative speed: same direction S1 โ S2; opposite S1 + S2
- Units: km/h ร 5/18 = m/s; m/s ร 18/5 = km/h
- Train: pole T = L รท S; platform (L + P) รท S; two trains (L1 + L2) รท (S1 ยฑ S2)
- Catch-up: head start รท (S1 โ S2). Meeting: gap รท (S1 + S2)
- Race: beats by x m in D m โ B : A = (D โ x) : D; by x m or t s โ B's speed = x รท t
- Boats: down b + s, up b โ s
- Circular track C: first meeting C รท (S1 ยฑ S2)
Frequently asked questions
What is relative speed?
How do you calculate the time a train takes to cross a platform?
How do you solve 'A beats B by x metres' race questions?
How do I convert km/h to m/s quickly?
Are train and race questions still asked in CLAT?
Keep going
Connected topics in other chapters
Every topic in Profit, Interest & Time-Speed-Work
- 1.Profit and Loss: CP, SP and Profit %
- 2.Marked Price and Discount: Mark-up, Sale Price and Profit
- 3.Successive Discounts and Discount Schemes: the Single Equivalent Discount
- 4.Cost, Revenue and Per-Unit Price in Caselets
- 5.Simple Interest: Formula, Shortcuts and CLAT Traps
- 6.Compound Interest and the SIโCI Difference
- 7.Speed, Distance and Time
- 8.Trains, Races and Relative Speed (you're here)
- 9.Time and Work: the LCM Method
- 10.Pipes and Cisterns